Checking Number Of Positive and Negative and Zero's Available

C Program For Checking Number Of Positive and Negative
and Zero's Available

Source Code:

#include<stdio.h>
#include<conio.h>

void main()
{
int i,n,num,c=0,d=0,e=0;
printf("enter num of element:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
printf("enter a num:");
scanf("%d",&num);
if(num<0)
{
c=c+1;
}
if(num==0)
{
d=d+1;
}
if(num>0)
{
e=e+1;
}
}
printf("num of pos=%d,num of zero=%d,num of neg=%d",c,d,e);
}


 OUTPUT:

enter num of element:5
enter a num:0
enter a num:-3
enter a num:6
enter a num:7
enter a num:-8
num of pos=2,num of zero=1,num of neg=2